Question 32861: The lenghth of a rectanguler room is 5 feet more than 3 times the width.Find the dimensions if the perimeter is 62 feet? Answer by sarah_adam(201) (Show Source):
You can put this solution on YOUR website! Let the length of the rectangular room be denoted as L ft
Let the width(breadth) of the rectangular room be denoted as B ft
Given Length of the room is 5 ft more than 3 times the Width
SO L = 5+3B
Also Given Perimeter P = 62 ft
The perimeter of a rectangle is the distance around the outside of the rectangle.
So the perimeter of the rectangle is 2(L+B)
2(L+B) = 62
2(5+3B+B) = 62 (replacing the value of L)
2(5+4B) = 62
5+4B = 62/2
5+4B = 31
4B = 31 - 5 = 26
B = 26/4 = 6.5 ft
L = 5 + 3(6.5)
L = 24.5 ft
So the dimensions of the room are L = 24.5 ft and Width of the room is 6.5 ft
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