Question 328583: In 2005, comsumers recieved, on average, 3253 spam messages. The volume of spam messages per consumer is decreasing exponentially with the exponential decay rate of 13.7% per year. Predict the number of spam messages received per consumer in 2010.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! In 2005, comsumers recieved, on average, 3253 spam messages.
The volume of spam messages per consumer is decreasing exponentially with the exponential decay rate of 13.7% per year.
---
A(t) = Ao*0.863^t
Predict the number of spam messages received per consumer in 2010.
---
A(5) = 3253*0.863^5
A(5) = 1557.18
Round up to 1558 in 2010
=========================
Cheers,
Stan H.
|
|
|