Question 32854: Find two consecutive odd integers such that for times the larger is 29 more than three times the smaller. Answer by sarah_adam(201) (Show Source):
You can put this solution on YOUR website! Let the two consequtive integers be x , x+2
Four times larger integer is 4(x+2) is 29 more than three times small integer
4(x+2) = 29 + 3(x)
4x + 8 = 29 + 3x
4x - 3x = 29 - 8
x = 21
x+2 = 23
therfore two consequtive odd integers are 21, 23