SOLUTION: 5. An airplane flies over an observer with a velocity of 400 mph and at an altitude of 2640 ft. If the plane flies horizontally in a straight line, find the rate at which the dista

Algebra ->  Human-and-algebraic-language -> SOLUTION: 5. An airplane flies over an observer with a velocity of 400 mph and at an altitude of 2640 ft. If the plane flies horizontally in a straight line, find the rate at which the dista      Log On


   



Question 328491: 5. An airplane flies over an observer with a velocity of 400 mph and at an altitude of 2640 ft. If the plane flies horizontally in a straight line, find the rate at which the distance x from the observer to the plane is changing 0.6 min after the plane passes over the observer. RE sketch below.
400 mph P

2640 ft X


O

Answer by galactus(183) About Me  (Show Source):
You can put this solution on YOUR website!
There a different ways to go about it, but I am going to convert everything to miles.
Since the plane is traveling 400 mph, in .6 minutes it travels x=4 miles.
We can build a right triangle. Let y=1/2 miles (2640 feet). This remains constant because the plane is not going higher or lower. Thus, dy/dt=0
dx/dt=400 mph
By Pythagoras, the distance from the observer to the plane is the hypoteneuse of the triangle: D=sqrt%28%281%2F2%29%5E2%2B4%5E2%29=sqrt%2865%29%2F2=4.031 miles.
So, we have D%5E2=x%5E2%2By%5E2
Differentiate implicitly w.r.t time(t).
D%2A%28dD%2Fdt%29=x%2A%28dx%2Fdt%29%2By%28dy%2Fdt%29
Enter in the knowns and solve for dD/dt, the rate of change of the distance between the observer and the plane.
sqrt%2865%29%2F2%2A%28dD%2Fdt%29=4%2A%28400%29%2B%281%2F2%29%280%29
1600%2F%28sqrt%2865%29%2F2%29=640%2Asqrt%2865%29%2F13=396.91 mph