SOLUTION: Solve the following equation over the interval [0.2pi). 4cos^2x=3

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Question 328425: Solve the following equation over the interval [0.2pi). 4cos^2x=3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4cos%5E2%28x%29=3
cos%5E2%28x%29=3%2F4
cos%28x%29=0+%2B-+sqrt%283%2F4%29
cos%28x%29=0+%2B-+sqrt%283%29%2F2
Four solultions:
x=pi%2F6, x=5pi%2F6,4=7pi%2F6,x=11pi%2F6