SOLUTION: Need Help Please! Failing this class... Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this. log9x = 1/2 I bel

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Need Help Please! Failing this class... Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this. log9x = 1/2 I bel      Log On


   



Question 328050: Need Help Please! Failing this class...

Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.
log9x = 1/2
I believe 9 is the base.

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
log(base 9)of x = 1/2 is the same thing as 9^(1/2) = x.
Now, 9^(1/2) = sqrt{9}, where sqrt = square root for short.
Then sqrt{9} = x
3 = x
The value of x is 3.