SOLUTION: a candy bowl contains * red M&M's, 5 blue, and 3 yellow. if two M&M's are selected @ random, what is the probability that one will be blue or one will be yellow?
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-> SOLUTION: a candy bowl contains * red M&M's, 5 blue, and 3 yellow. if two M&M's are selected @ random, what is the probability that one will be blue or one will be yellow?
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Question 328012: a candy bowl contains * red M&M's, 5 blue, and 3 yellow. if two M&M's are selected @ random, what is the probability that one will be blue or one will be yellow? Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! I assume you mean reds? Red Blue Yellow total
I assume you mean two are chosen without replacement.
P(1B or 1Y) means P(not both reds)
Find P(not both reds)
P(both reds)+P(not both reds)=
P(not both reds)=-P(both reds)
.
.
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P(R,R)=
P(not both reds)=
P(1B or 1Y)=
