Question 32801This question is from textbook Addison Wesley Geometry
: Chapter is tittled "Right Triangle Relationships"
Where the altitude is MQ and the hypotenuse is NP.......... The question is this: If MN = 8, QN = 6, What is PN? I have tried to help my 9th grader, but Geometry was not my strong subject when I was in high school. He has a quiz over this tomorrow. Any chance anyone is out there who can help with the answer and explanation yet tonight so he can look at it and understand it in the morning before he goes to school?
This question is from textbook Addison Wesley Geometry
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! PLEASE GIVE COMPLETE NOMENCLATURE LIKE WHAT IS THE TRIANGLE NAME ETC..
Where the altitude is MQ and the hypotenuse is NP.......... The question is this: If MN = 8, QN = 6, What is PN? I have tried to help my 9th grader, but Geometry was not my strong subject when I was in high school. He has a quiz over this tomorrow. Any chance anyone is out there who can help with the answer and explanation yet tonight so he can look at it and understand it in the morning before he goes to school?
OK ASSUMING MNP IS THE TRIANGLE,ANGLE NMP=90...AND SINCE MQ IS THE ALTITUDE,ANGLE NQM =90
IN TRIANGLES MNQ AND PNM...
ANGLE MQN=90=ANGLE NMP
ANGLE MNQ=ANGLE MNP....
SO THE 2 TRIANLES ARE SIMILAR..HENCE
MN/PN=NQ/NM
8/PN=6/8
6*PN=8*8=64
PN=64/6=32/3=10.667
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