SOLUTION: y^2=4/5y+4/7= 2 real solutions, one real or two non-real. I say one real because the fractions are opposites of each other? Right? x^2+6x+9=25 solve for x In this equation it asks

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: y^2=4/5y+4/7= 2 real solutions, one real or two non-real. I say one real because the fractions are opposites of each other? Right? x^2+6x+9=25 solve for x In this equation it asks       Log On


   

Question 327999: y^2=4/5y+4/7= 2 real solutions, one real or two non-real. I say one real because the fractions are opposites of each other? Right? x^2+6x+9=25 solve for x In this equation it asks for an exact amount.Couldn't I factor this one out to find the value? 9x^2+12x+4 find x and y intercepts At total loss on this one.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4/5 and 4/7 are opposites? How?
Either graph the equation or use the discriminant to determine the number of real roots.
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y%5E2-%284%2F5%29y-4%2F7=0
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graph%28300%2C300%2C-5%2C5%2C-10%2C10%2Cx%5E2-%284%2F5%29x-4%2F7%29
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The function crosses the x axis twice, two real roots.
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x%5E2%2B6x%2B9=25+
x%5E2%2B6x-16=0
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graph%28300%2C300%2C-10%2C10%2C-15%2C5%2Cx%5E2%2B6x-16%29
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How many roots? What are they?
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9x%5E2%2B12x%2B4=0
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graph%28300%2C300%2C-3%2C3%2C-1%2C5%2C9x%5E2%2B12x%2B4%29
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x-intercept: Where does the function cross the x-axis?
y-intercept: Where does the function cross the y-axis? Value for f(x) when x=0.
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You can't factor x out but you can factor two of the equations.
For the first equation, you need to either complete the square or use the quadratic formula.
Equation 2:
x%5E2%2B6x-16=0
%28x-2%29%28x%2B8%29=0
Two solutions:
x=2 and x=-8 are the x-intercepts.
y=0%5E2%2B6%280%29-16=-16 is the y-intercept.
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Equation 3:
y=9x%5E2%2B12x%2B4=0
%283x%2B2%29%283x%2B2%29=0 <--- Double root
3x%2B2=0
x=-2%2F3 is the x-intercept
y=9%280%29%5E2%2B12%280%29%2B4=4 is the y-intercept