SOLUTION: I'm not sure if I'm in the right section, but I would really appreciate help with this problem it says prove that mx-y=b and x+my=c are perpendicular.

Algebra ->  Linear-equations -> SOLUTION: I'm not sure if I'm in the right section, but I would really appreciate help with this problem it says prove that mx-y=b and x+my=c are perpendicular.       Log On


   

Question 32764: I'm not sure if I'm in the right section, but I would really appreciate help with this problem it says prove that mx-y=b and x+my=c are perpendicular.
Answer by askmemath(368) About Me  (Show Source):
You can put this solution on YOUR website!
If two lines are perpendicular, the product of their slopes = -1
So first we find the slopes of both the lines
mx-y=b
This can be re-written as
y = mx-b <--Slope Intercept Form
Slope in this case = m
x+my=c
my = -x +c
y+=+-x%2Fm+%2Bc%2Fm
Slope in this case = -1%2Fm
Now product of the 2 slopes = m+%2A%28-1%2Fm%29
= -1
Hence the two lines are Perpendicular