SOLUTION: a wire of length 200 cm is cut into two parts and each part of wire is bent to form a square.If area of large square is 9 times the area of small square find perimeter of large squ
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Question 327606: a wire of length 200 cm is cut into two parts and each part of wire is bent to form a square.If area of large square is 9 times the area of small square find perimeter of large square Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let one part be x
and the other part will be 200-x
..
Area of square = L^2
area of one square = x^2
area of other square = (200-x)^2
9x^2= (200-x)^2
9x^2=40000-400x+x^2
add -4x^2 to both sides
9x^2-9x^2=40000-400x+x^2-9x^2
-1(8x^2+400x-40000)=0
Take out 8 which is common
-8(x^2+50x-5000)=0
divide by -8
x^2+100x-50x-5000=0
x(x+100)-50(x+100)=0
(x+100)(x-50)=0
x=-100 OR 50
..
ignore the negative
so one part is 50 cm.
The other part is 150 cm.
The perimeter of the larger square is 150 cm.
