SOLUTION: The length of a rectangle is 7 foot less than 2 times the width. Find the dimensions of this rectangle if the area is 72 square fee
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Question 327605: The length of a rectangle is 7 foot less than 2 times the width. Find the dimensions of this rectangle if the area is 72 square fee Answer by unlockmath(1688) (Show Source):
You can put this solution on YOUR website! Hello,
Let's have x represent the width. So the length will be shown as 2x-7. Now we can set up an equation as:
x(2x-7)=72
Now expand this out to:
2x^2-7x=72
Subtract 72 from both sides to get:
2x^2-7x-72=0
Now factor this:
(2x+9)(x-8)=0
Now solve for x
x=-9/2
x=8
The only one that makes sense here is:
8 feet for the width
And the length will be:
9 feet.
Make sense?
RJ
www.math-unlock.com
