Question 327602: Three hundred people attended the premiere of a motion picture. Adult tickets costs $10 each and children were admitted for $6 each. If the box office receipts totaled $ 1200; how many children attended?
Found 2 solutions by Fombitz, unlockmath:
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! Something is wrong with your problem setup.
If all 300 tickets were Adults, the total receipts would have been $3,000.
If all 300 tickets were Children, the total receipts would have been $1,800.
So the total receipts must range between $1,800 and $3,000.
A total of $1,200 is not possible and leads to a solution of 450 Childrens tickets and -150 Adult tickets, which is a nonsensical solution.
Please check your problem setup and repost.
Answer by unlockmath(1688)  (Show Source):
You can put this solution on YOUR website! Hello,
We can set up 2 equations for this one. Let C represent children and A for adults.
C+A=300
6C+10A=1200
Use substitution method. Set up the first equation as C=300-A and plug it into the second as:
6(300-A)+10A=1200
Now expand it our and combine like terms to get:
1800+4A=1200
Subtract 1800 to get:
4A=-600
Divide by 4 to get:
A=-125
As you can see from this it's impossible to have negative 125 Adults.
See if you copied the problem correctly from the book.
RJ
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