SOLUTION: Please help!? 3x^3y^2 – 3x^2y^2 + 3xy^2 --wouldn't this be prime, so no further factoring? Only 0 and 3 would work for the sum, and that won't work for the product....
Help
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Please help!? 3x^3y^2 – 3x^2y^2 + 3xy^2 --wouldn't this be prime, so no further factoring? Only 0 and 3 would work for the sum, and that won't work for the product....
Help
Log On
Question 327349: Please help!? 3x^3y^2 – 3x^2y^2 + 3xy^2 --wouldn't this be prime, so no further factoring? Only 0 and 3 would work for the sum, and that won't work for the product....
Help?!?? Answer by jvan(28) (Show Source):
You can put this solution on YOUR website! You can pull out common variables and numbers from each of these terms. They share . Pulling out from all of them makes [(3*x^3*y^2) – (3*x^2*y^2) + (3*x*y^2)] become . There is no way you can factor x^2-x+1 without using imaginary numbers, so you can stop there :) Thus, is your answer. ****---->If you need anymore help, please visit my website at http://myonlinetutor.webs.com and become a member ^0^!