SOLUTION: The sum of three consecutive odd integers equals one less than for times the smallest integer. What are the integers. Answer known. Need to understand process. Thanks

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Question 327335: The sum of three consecutive odd integers equals one less than for times the smallest integer. What are the integers. Answer known. Need to understand process. Thanks
Found 2 solutions by Fombitz, mananth:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The three consecutive integers are N, N+1, and N+2.
N%2BN%2B1%2BN%2B2=4N-1
3N%2B3=4N-1
N=4
The integers are then 4,5, and 6.
Verify,
%284%2B5%2B6%29=4%284%29-1
15=16-1
15=15
True, good solution

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of three consecutive odd integers equals one less than for times the smallest integer.
..
let the smallest odd integer be x
next will be x+2
third will be x+4
Their sum = x+x+2+x+4= 3x+6.............1
..
smallest integer = x
4 times the number = 4x
1 less than 4 times the number
4x-1....................................2
3x+6=4x-1
add -6 to both sides
3x+6-6=4x-1-6
3x=4x-7
add -4x to both sides
3x-4x=4x-4x-7
-x=-7
divide both by -1
-x/-1 = -7/-1
x=7
the numbers are 7, 9, 11