SOLUTION: find the maximum or minimum value of the function defined by f(x)=-x^2-6x-8

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Question 327053: find the maximum or minimum value of the function defined by f(x)=-x^2-6x-8
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square to put the equation in vertex form, y=a%28x-h%29%5E2%2Bk, the min or max value of the function occurs at the vertex.
f%28x%29=-x%5E2-6x-8
f%28x%29=-%28x%5E2%2B6x%29-8
f%28x%29=-%28x%5E2%2B6x%2B9%29-8%2B9
f%28x%29=-%28x%2B3%29%5E2%2B1
Since the coefficient of the x%5E2 term is negative, the parabola opens downward and the value at the vertex is a maximum.
The vertex (h,k) is (-3,1).
ymax=1
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