SOLUTION: The length of a rectangle is 4 feet more than twice the length. The area of the rectangle is 48 ft square. Find the length and the width of the rectangle.
Algebra ->
Rectangles
-> SOLUTION: The length of a rectangle is 4 feet more than twice the length. The area of the rectangle is 48 ft square. Find the length and the width of the rectangle.
Log On
Question 326928: The length of a rectangle is 4 feet more than twice the length. The area of the rectangle is 48 ft square. Find the length and the width of the rectangle. Answer by AAfter Search(61) (Show Source):
You can put this solution on YOUR website! Let the length and width of the rectangle be 2w + 4 and w.
Area of the rectangle is Length X Breadth i.e.,
(2w + 4) x w = 48
=> 2w^2 + 4w = 48
=> 2w^2 + 4w - 48 = 0
=> w^2 + 2w - 24 = 0
=> w^2 + 6w - 4w - 24 = 0
=> w(w+ 6) - 4(w + 6) = 0
=> (w - 4)(w + 6) = 0
=> w = 4, -6.
Negative value of w is inappropriate.
Hence, width w is 4 feet.
Length is 2 x 4 + 4 = 8 + 4 = 12 feet.
(