SOLUTION: in a particular game, a fair die is tossed. if the number of spots showing is a six, you win $6, if the number of spots showing is a five, you win $3, and if the number of spots sh
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-> SOLUTION: in a particular game, a fair die is tossed. if the number of spots showing is a six, you win $6, if the number of spots showing is a five, you win $3, and if the number of spots sh
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Question 326911: in a particular game, a fair die is tossed. if the number of spots showing is a six, you win $6, if the number of spots showing is a five, you win $3, and if the number of spots showing is 4, you win $1. if the number of spots showing is 1, 2, or 3 you win nothing. you are going to play the game twice.
The probability that you win over $10 in total on the two plays of the game is:
a- 1/6
b- 1/3
c- 1/36
d- 1/4
thanks Answer by solver91311(24713) (Show Source):
The only way to get more than $10 in two plays is to roll a 6 twice. Rolling one die twice or two dice at the same time is identical from a probability standpoint. Probability of Boxcars is 1 in 36.
