SOLUTION: find the coordinates of the vertex for the parabola f(x) =4xsquared-x+2

Algebra ->  Linear-equations -> SOLUTION: find the coordinates of the vertex for the parabola f(x) =4xsquared-x+2      Log On


   

Question 326889: find the coordinates of the vertex for the parabola f(x) =4xsquared-x+2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to vertex form by completing the square,
f%28x%29=4x%5E2-x%2B2
f%28x%29=4%28x%5E2-%281%2F4%29x%29%2B2
f%28x%29=4%28x%5E2-%281%2F4%29x%2B1%2F64%29%2B2-4%2F64
f%28x%29=4%28x-1%2F8%29%5E2%2B128%2F64-4%2F64
f%28x%29=4%28x-1%2F8%29%5E2%2B31%2F16
The vertex is (1/8,31,16).
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