Question 326888: Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each? Can you sow all of your work so I can understand it more? Thanks in advance!
Answer by jessica43(140)   (Show Source):
You can put this solution on YOUR website! To solve this problem, you are going to have to first write two equations using what you know.
First, you know that Tony and Belinda have a combined age of 56. This can be written as:
T + B = 56 (where T = Tony's age, B = Belinda's age)
Second, you know that Belinda is 8 more than twice Tony's age. This can be written as:
B = 8 + 2T
Now you can plug in the second equation into the first equation for B and solve for T:
T + B = 56
T + (8 + 2T) = 56
8 + 3T = 56
3T = 48
T = 16
So Tony is 16 years old.
Now plug this into the first equation to find B:
T + B = 56
16 + B = 56
B = 40
So Belinda is 40 years old.
Hope that helps!
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