SOLUTION: In using the factoring method of solving quadratic equations, we put it in the form: (x+a)(x+b) = 0. Where a and b are two constants (think of them as two “numbers”). If the

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: In using the factoring method of solving quadratic equations, we put it in the form: (x+a)(x+b) = 0. Where a and b are two constants (think of them as two “numbers”). If the      Log On


   



Question 326332: In using the factoring method of solving quadratic equations, we put it in the form:
(x+a)(x+b) = 0. Where a and b are two constants (think of them as two “numbers”).
If the right-hand side of this equation is not zero (let’s say another constant "c"), do you think it can be solved? If so, how? If not, why not?

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let's presume you are faced with the equation:



Where , , and are constants.

Step one is to apply FOIL to the two binomials in the LHS.



Then add to both sides.



Then combine the constants so that and to write:



Then, if you can find numbers and such that and , then you can factor your equation:



which has roots and

barring that you can use the quadratic formula to write:



to find your two roots.


John