SOLUTION: Hi i have 2 graphs y=8+2cos((pix)/6) and y= 3.5+e^(0.07x) and i need to find the values of x when y1=y2 aka 8+2cos((pix)/6)= 3.5+e^(0.07x but don't know how to do it any help would
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-> SOLUTION: Hi i have 2 graphs y=8+2cos((pix)/6) and y= 3.5+e^(0.07x) and i need to find the values of x when y1=y2 aka 8+2cos((pix)/6)= 3.5+e^(0.07x but don't know how to do it any help would
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Question 326331: Hi i have 2 graphs y=8+2cos((pix)/6) and y= 3.5+e^(0.07x) and i need to find the values of x when y1=y2 aka 8+2cos((pix)/6)= 3.5+e^(0.07x but don't know how to do it any help would be great. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
Three solutions from www.wolframalpha.com, just type in the equation
8+2cos((pi*x)/6)=(3.5+e^(0.07x))
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http://www.wolframalpha.com/input/?i=8%2B2cos%28%28pi*x%29%2F6%29%3D%283.5%2Be%5E%280.07x%29%29
