Question 326320: What is log b (base) (5x^5)/(yz^6)
And:
4^2x+3=67
Answer by user_dude2008(1862)   (Show Source):
You can put this solution on YOUR website! log(b, (5x^5)/(yz^6) )
log(b, (5x^5) )- log(b, (yz^6) )
log(b, 5) +log(b, x^5)- (log(b, y) +log(b,z^6) )
log(b, 5) +5log(b, x)- log(b, y) -6log(b,z)
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4^(2x)+3=67
4^(2x)=64
2x=log(4,64)
2x=3
x=3/2
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