SOLUTION: Find the values of k that will make the solutions of the given quadratic equation equal. kx^2 - 10x + 5 = 0

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Question 326302: Find the values of k that will make the solutions of the given quadratic equation equal.

kx^2 - 10x + 5 = 0

Found 2 solutions by AAfter Search, mananth:
Answer by AAfter Search(61) About Me  (Show Source):
You can put this solution on YOUR website!
If the solutions of a quadratic equation are equal, then its discriminant should be equal to zero.
The given equation is kx^2 - 10x + 5 = 0
Hence, Discriminant D = [(-10)^2 - 4 x k x 5] = 0
=> (100 - 20k) = 0
=> 100 = 20k
=> k 100/20 = 5.
Hence, for k = 5, the solutions of the given quadratic equation are equal.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
kx^2-10x+5=0
in the general equation ax^2+bx +c
for the roots to be equal
b^2-4ac=0
b=-10, a=k,c=5
..
(-10)^2-4*k*5 =0
100-20k=0
add 20k to both sides
100-20k%2B20k=20k
100=20k
divide+by+20
100%2F20=20k%2F20
5=k