SOLUTION: A rectangle is 2 inches longer than it is wide. Numerically, its area exceeds its perimeter by 44. Find the perimeter.

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Question 326296: A rectangle is 2 inches longer than it is wide. Numerically, its area exceeds its perimeter by 44. Find the perimeter.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
width = x
length = x+2
area = x(x+2)
..
Perimeter = 2x+ 2(x+2)
= 2x+2x+4
=4x+4
x%28x%2B2%29-4x%2B4=44
x%5E2%2B2x-4x-4-44=0
x%5E2-2x-48=0
x%5E2-8x%2B6x-48=0
x%28x-8%29%2B6%28x-8%29=0
%28x%2B6%29%28x-8%29=0
x=-6 x=8 Ignore negative value
width = 8 inches
length = 10 inches