SOLUTION: 4x-2y=16 5x+7y=1 We eliminate. y from 1 to get 2y=4x-16 y=2x-8 We then substitute. in the 2nd equation 5x+14x-56=1 19x=57=x=3, y=6-8=-3 x=3 y=-2 Can some tell me if I did t

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Question 326107: 4x-2y=16
5x+7y=1
We eliminate. y from 1 to get 2y=4x-16 y=2x-8
We then substitute. in the 2nd equation 5x+14x-56=1 19x=57=x=3, y=6-8=-3
x=3
y=-2
Can some tell me if I did this right? I was suppose to solve using the elimination method. Thanks
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

In a word, No. You did obtain the correct values of the coordinates of the ordered pair that is the solution set of the system. However, you solved it by the Substitution Method, NOT the Elimination Method.

Eq. 1:

Eq. 2:

Multiply 1 by 7 and 2 by 2:

Eq. 3:

Eq. 4:

Add 3 to 4:

Here is where one of the variables ( in this case) was eliminated.

NOW you can substitute:

See the difference? Note that you could also have multiplied 1 by 5 and 2 by -4 and that would have allowed you to eliminate . The result, of course, would have been the same.

By the way, the answer is most properly expressed as an ordered pair, or rather a set containing a single ordered pair, namely

John