SOLUTION: two boats leave at the same time, one goin north and the other goin souththe north ound boat travels at 16mph. faster than the boat going south. If south bound boat is traveling 47

Algebra ->  Angles -> SOLUTION: two boats leave at the same time, one goin north and the other goin souththe north ound boat travels at 16mph. faster than the boat going south. If south bound boat is traveling 47      Log On


   

Question 326008: two boats leave at the same time, one goin north and the other goin souththe north ound boat travels at 16mph. faster than the boat going south. If south bound boat is traveling 47mph how long before they are 1430 miles apart
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
south bound boat speed = 47mph
north bound boat speed = 47+16 = 63 mph
..
let north bound boat be x miles from starting point when they are 1430 miles apart
south bound boat will be 1430-x miles
..
They travel these distances in the same time
time of north bound boat = x/63
time of south bound boat = 1430-x/47
x%2F63=+%281430-x%29%2F47
47x=63%2A%281430-x%29
47x=+90090-63x
Add 63x to both sides
47x%2B63x=90090-63x%2B63x
110x=90090
divide by 110
110x%2F110=+90090%2F110
x=+819+miles
The speed of north bound boat =63mph
distance it has traveled = 819 miles
Time taken = +819%2F63
Time taken = 13 hours
..
..
CHECK
south bound boat travels
1430-819=611miles when they are 1430 miles apart
speed = 47 mph
time = 611/47
time = 13 hours