SOLUTION: I am stuck on a word problem: A woman has $16,000 invested in stock A and stock B. Stock A sells for $30 a share and stock B sells for $70 a share. If stock B triples in value and

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I am stuck on a word problem: A woman has $16,000 invested in stock A and stock B. Stock A sells for $30 a share and stock B sells for $70 a share. If stock B triples in value and      Log On


   

Question 325955: I am stuck on a word problem: A woman has $16,000 invested in stock A and stock B. Stock A sells for $30 a share and stock B sells for $70 a share. If stock B triples in value and stock A goes up 50%, her stock will be worth $34,500. How many shares of each stock does she own?
I set up two equations that I think represent the problem: 30a+%2B+70b=16000 and 45a%2B210b=34500. Am I on the right track?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
you are right on track . just solve for x & y