SOLUTION: Joe can paint a house in 7 hours. Moe can paint a house in 10 hours. if they both start on the house together at 7am and Moe takes an hour lunch break, when will they finish the ho

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Joe can paint a house in 7 hours. Moe can paint a house in 10 hours. if they both start on the house together at 7am and Moe takes an hour lunch break, when will they finish the ho      Log On


   

Question 325954: Joe can paint a house in 7 hours. Moe can paint a house in 10 hours. if they both start on the house together at 7am and Moe takes an hour lunch break, when will they finish the house?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


If A can do a job in x time periods, then A can do of the job in 1 time period. Likewise, if B can do the same job in y time periods, then B can do of the job in 1 time period.

So, working together, they can do



of the job in 1 time period.

Therefore, they can do the whole job in:



time periods.

So and

hrs.

Or 4 hrs 7 minutes give or take a few seconds. That means that if they start at 7AM, they will be done by 11:07 and Moe takes his lunch break AFTER they are done.


John