You can put this solution on YOUR website! 4^11 x 5^21 = 2 x 10^n
=> (2^2)^11 x 5^21 = 2^1 x (2x5)^n
=> 2^22 x 5^21 = 2^(1 + n) x 5^n
=> Comparing the exponents of 5 on both sides of equality sign, we get n = 21.
The same result is found from the exponent of 2.