SOLUTION: x^2/(3x^2-11x+6) - 4/(x-3) = -2/(3x-2) I get x^2 - 4(3x-2) = -2(x-3) x^2 - 12x + 8 + -2x+6 x^2 - 10x +2 ?????? where did i go wrong?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: x^2/(3x^2-11x+6) - 4/(x-3) = -2/(3x-2) I get x^2 - 4(3x-2) = -2(x-3) x^2 - 12x + 8 + -2x+6 x^2 - 10x +2 ?????? where did i go wrong?       Log On


   

Question 325471: x^2/(3x^2-11x+6) - 4/(x-3) = -2/(3x-2)
I get
x^2 - 4(3x-2) = -2(x-3)
x^2 - 12x + 8 + -2x+6
x^2 - 10x +2
?????? where did i go wrong?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You're off to a great start. You just need to solve x%5E2+-+10x+%2B2=0 now.


x%5E2-10x%2B2=0 Start with the given equation.


Notice that the quadratic x%5E2-10x%2B2 is in the form of Ax%5E2%2BBx%2BC where A=1, B=-10, and C=2


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-10%29+%2B-+sqrt%28+%28-10%29%5E2-4%281%29%282%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-10, and C=2


x+=+%2810+%2B-+sqrt%28+%28-10%29%5E2-4%281%29%282%29+%29%29%2F%282%281%29%29 Negate -10 to get 10.


x+=+%2810+%2B-+sqrt%28+100-4%281%29%282%29+%29%29%2F%282%281%29%29 Square -10 to get 100.


x+=+%2810+%2B-+sqrt%28+100-8+%29%29%2F%282%281%29%29 Multiply 4%281%29%282%29 to get 8


x+=+%2810+%2B-+sqrt%28+92+%29%29%2F%282%281%29%29 Subtract 8 from 100 to get 92


x+=+%2810+%2B-+sqrt%28+92+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%2810+%2B-+2%2Asqrt%2823%29%29%2F%282%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%2810%29%2F%282%29+%2B-+%282%2Asqrt%2823%29%29%2F%282%29 Break up the fraction.


x+=+5+%2B-+sqrt%2823%29 Reduce.


x+=+5%2Bsqrt%2823%29 or x+=+5-sqrt%2823%29 Break up the expression.


So the solutions are x+=+5%2Bsqrt%2823%29 or x+=+5-sqrt%2823%29