SOLUTION: the present age of a women is three years more that three times the age of her daughter. three years hence, the womans age will be ten years more than twice the age of her daughter

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the present age of a women is three years more that three times the age of her daughter. three years hence, the womans age will be ten years more than twice the age of her daughter      Log On


   



Question 325361: the present age of a women is three years more that three times the age of her daughter. three years hence, the womans age will be ten years more than twice the age of her daughter. find their present ages.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
the present age of a women is three years more that three times the age of her daughter.
---
m = 3d
---
three years hence, the womans age will be ten years more than twice the age of her daughter.
---
(m+3) = 2(d+3)+10
---
find their present ages.
---
Substitute for "m" and solve for "d":
(3d+3) = 2(d+3)+10
3d+3 = 2d+6+10
d = 13 (daughter's age NOW)
---
Since m = 3d, m = 39 (mother's age NOW)
==============================
Cheers,
Stan H.