SOLUTION: Divide 300 into two parts so that half of one part may be less than the other by 48

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Divide 300 into two parts so that half of one part may be less than the other by 48      Log On


   

Question 325335: Divide 300 into two parts so that half of one part may be less than the other by 48
Answer by AAfter Search(61) About Me  (Show Source):
You can put this solution on YOUR website!
Solution: Let x + y = 300, where x and y are two (parts)numbers
Given, x - y/2 = 48
=> x = 48 + y/2
Hence, 48 + y/2 + y = 300
3y/2 = 252
y = 2 X 252 / 3 = 504 / 3 = 168
x = 300 - 168 = 132
Hence, the two parts (numbers)are 132 and 168.