SOLUTION: You will need to use the formula 4.9t^2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters.
Approximately how far will an obje
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Quadratic Equations and Parabolas
-> SOLUTION: You will need to use the formula 4.9t^2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters.
Approximately how far will an obje
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Question 325154: You will need to use the formula 4.9t^2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters.
Approximately how far will an object fall in 13 seconds (t) when thrown downward at an initial velocity of 10 meters per second (v0) from a plane? Found 2 solutions by stanbon, Alan3354:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! You will need to use the formula 4.9t^2 + v0t = s(t), where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters.
Approximately how far will an object fall in 13 seconds (t) when thrown downward at an initial velocity of 10 meters per second (v0) from a plane?
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s(13) = 4.9(13)^2 + 10(13)
S(13) = 958.1 ft.
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Cheers,
Stan H.
You can put this solution on YOUR website! Approximately how far will an object fall in 13 seconds (t) when thrown downward at an initial velocity of 10 meters per second (v0) from a plane?
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s(13) = 4.9(13)^2 + 10(13)
S(13) = 958.1 meters
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