Question 325058: What line is perpendicular to y=3/5x+1 but contains (5,2)?
Answer by nyc_function(2741)   (Show Source):
You can put this solution on YOUR website! Slopes of perpendicular lines are negative reciprocals of each other.
Your given slope is 3/5. The slope of the equation we want to find is -5/3.
We use the point-slope formula: y - a = m(x - b), where the given point (5,2) represents the general point (b,a).
NOTE: I used a and b to represent the given point but you can use any two letters of choice.
Let m = -5/3
Let a = 2
Let b = 5
y - 2 = (-5/3)(x - 5)
y - 2 = (-5/3)(x) + (25/3)
y = (-5/3)(x) + (25/3) + 2
y = (-5/3)(x) + (31/3)
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