SOLUTION: In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president. If 100 registered voters were sampled randomly, it was found that 35% woul

Algebra ->  Probability-and-statistics -> SOLUTION: In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president. If 100 registered voters were sampled randomly, it was found that 35% woul      Log On


   

Question 325019: In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president. If 100 registered voters were sampled randomly, it was found that 35% would vote of the incumbent. Test the claim that the actual proportion is 43%. Let level of significance = 0.01. (Round phat to 2 decimal places.)


1. H0 :
Ha :
2. Level of significance =
3. Test statistics:
4. P-value or critical z0 or t0.
5. Rejection Region:
6. Decision:
7. Interpretation:

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president.
If 100 registered voters were sampled randomly, it was found that 35% would vote of the incumbent.
Test the claim that the actual proportion is 43%. Let level of significance = 0.01. (Round phat to 2 decimal places.)

1.
H0 : p = 0.43
Ha : p is not 0.43
----------------------------------
2. Level of significance = 1%
-----
3. Test statistics: z(0.35) = (0.35-0.43)/sqrt(0.43*0.57/100) = -16.16
---
4. P-value or critical z0 or t0.
p-value = 2*P(z< -16.16) = zero to 4 decimal places
--------
5. Rejection Region: z< -2.5758 and z> 2.5758
--------------------------------
6. Decision: Reject Ho.
Test results do not support claim that p = 0.43.
======================
Cheers,
Stan H.
7. Interpretation: