SOLUTION: In parallelogram ABCD, AB = 31, BC = 20, CD = 5x + 3y, and DA = 3x + 2y. Find the lengths of the sides of the parallelogram.

Algebra ->  Parallelograms -> SOLUTION: In parallelogram ABCD, AB = 31, BC = 20, CD = 5x + 3y, and DA = 3x + 2y. Find the lengths of the sides of the parallelogram.      Log On


   



Question 324992: In parallelogram ABCD, AB = 31, BC = 20, CD = 5x + 3y, and DA = 3x + 2y. Find the lengths of the sides of the parallelogram.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I think you mean find x and y since you already know the lengths of the sides.
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AB=CD
BC=DA
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1.5x+%2B+3y=31
2.3x+%2B+2y=20
Multiply eq. 1 by -2 and eq. 2 by 3 and add them,
-10x-6y%2B9x%2B6y=-62%2B60
-x=-2
highlight%28x=2%29
Then use either equation to solve for y,
10%2B3y=31
3y=21
highlight%28y=7%29