SOLUTION: If m and n are consecutive even integers and m > n > 0, how many integers are greater than m + n and less than mn? (A) 1 (B) 2 (C) m _ n (D) n^2 _ 3 (E) m^2 _ n^2

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: If m and n are consecutive even integers and m > n > 0, how many integers are greater than m + n and less than mn? (A) 1 (B) 2 (C) m _ n (D) n^2 _ 3 (E) m^2 _ n^2       Log On


   



Question 324991: If m and n are consecutive even integers and m > n > 0, how many integers are greater than m + n and less than mn?
(A) 1
(B) 2
(C) m _ n
(D) n^2 _ 3
(E) m^2 _ n^2

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
m=J%2B2
n=J
m%2Bn=J%2B2%2BJ=2J%2B2
mn=%28J%2B2%29J=J%5E2%2B2J
The number of integers between m%2Bn and mn is mn-%28m%2Bn%29-1.
What is the value of mn-%28m%2Bn%29-1 in terms of J?
mn-%28m%2Bn%29-1+=+J%5E2%2B2J-2J-2-1
mn-%28m%2Bn%29=+J%5E2-3
mn-%28m%2Bn%29=+n%5E2-3
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.
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D) is the solution.