Question 324858: the perimeter of rectangle is 42 m. the length of the rectangle is 3 m less than twice the width. find the length and the width of the rectangle.
Answer by jessica43(140)   (Show Source):
You can put this solution on YOUR website! To solve this problem you need to use the given information to write two equations and then solve.
First,you know that a rectangle has 4 sides with each of the opposite sides having the same length, and the total perimeter is 42m. So:
W+W+L+L = 42 or 2W + 2L = 42 (with W=width and L= length)
Second,you know that the length of the rectangle is 3m less than twice the width, which can be written as:
L = 2W - 3
Now you can plug the second equation into the first equation, replacing the L value:
2W + 2L = 42
2W + 2(2W-3) = 42
2W + 4W - 6 = 42
6W - 6 = 42
6W = 48
W = 8
Now plug this into the second equation to find the length:
L = 2W - 3
L = 2(8) - 3
L = 16-3
L = 13
So the width of the rectangle is 8 meters and the length is 13 meters.
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