SOLUTION: your radiator holds 5 gallons of fluid. if it is full with a 15% solution, how much fluid should be drained and replaced with a 65% antifreeze mixture to result in a 40% mixture of

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Question 324843: your radiator holds 5 gallons of fluid. if it is full with a 15% solution, how much fluid should be drained and replaced with a 65% antifreeze mixture to result in a 40% mixture of antifreeze?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
your radiator holds 5 gallons of fluid. if it is full with a 15% solution, how much fluid should be drained and replaced with a 65% antifreeze mixture to result in a 40% mixture of antifreeze?
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active - active + active = active
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0.15*5 - 0.15x + 0.65x = 0.40*5
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Multiply thru by 100 to get:
15*5 - 15x + 65x = 40*5
50x = 25*5
x = (1/2)(5)
x = 2.5 gallons (amt. of 15% solution that
should be replaced with 65% solution.
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Cheers,
Stan H.
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