SOLUTION: Find all values for K so that the equation 3t(squared)-6t+k=0 has two real roots

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Question 324813: Find all values for K so that the equation 3t(squared)-6t+k=0 has two real roots
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find the discriminant.
D=b%5E2-4ac
D=%28-6%29%5E2-4%283%29%28k%29
D=36-12k
In order to have real roots, D%3E=0
36-12k%3E=0
-12k%3E=-36
highlight%28k%3C=3%29