SOLUTION: Given y = -3/2x + 7/2 a) find the equation of a parallel line that contains the point (2,6) b) find the equation of a perpendicular line that contains the origin

Algebra ->  Graphs -> SOLUTION: Given y = -3/2x + 7/2 a) find the equation of a parallel line that contains the point (2,6) b) find the equation of a perpendicular line that contains the origin       Log On


   

Question 324720: Given y = -3/2x + 7/2
a) find the equation of a parallel line that contains the point (2,6)
b) find the equation of a perpendicular line that contains the origin
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel lines have identical slopes.
Your new line will have the form,
y=-%283%2F2%29x%2Bb
Use the point (2,6) to solve for b.
6=-%283%2F2%292%2Bb
b-3=6
b=9
highlight%28y=-%283%2F2%29x%2B9%29
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Perpendicular lines have slopes that are negative reciprocals.
m1%2Am2=-1
-%283%2F2%29%2Am2=-1
m2=2%2F3
y=%282%2F3%29x%2Bb
If the point is the origin then,
0=%282%2F3%29%280%29%2Bb%0D%0A%7B%7B%7Bb=0
highlight%28y=%282%2F3%29x%29
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