Question 324683: how many mL of each of 45% solution and a 15% solution should be mixed in order to obtain 25 mL of a 30% solution? Found 2 solutions by stanbon, modi.kk91:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how many mL of each of 45% solution and a 15% solution should be mixed in order to obtain 25 mL of a 30% solution?
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Equation:
active + active = active
0.45x + 0.15(25-x) = 0.30(25)
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Multiply thru by 100 to get:
45x + 15*25 - 15x = 30*25
30x = 15*25
x = 12.5 mL (amt. of 45% solution needed in the mix)
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25-x = 12.5 mL (amt of 15% solution needed in the mix)
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Cheers,
Stan H.
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