SOLUTION: ((( cindy has $6.05 in quarters and nickels. How many of each coin does she have if there are 53 coins in all.)))) Can you please help me set up this problem

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: ((( cindy has $6.05 in quarters and nickels. How many of each coin does she have if there are 53 coins in all.)))) Can you please help me set up this problem      Log On


   



Question 32459: ((( cindy has $6.05 in quarters and nickels. How many of each coin does she have if there are 53 coins in all.)))) Can you please help me set up this problem
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X+Y=53 AND 5X+25Y=605 X=53-Y SUBSTITUTING IN THE SECOND EQUATION WE GET
5(53-Y)+25Y=605 OR 265-5Y+25Y=605 OR 20Y=340 OR Y=17 THEREFORE X=53-17 OR X=36
PROOF 5*36+17*25=605 OR 180+425=605 OR 605=605