SOLUTION: 5^2x+1=125^x My answer 5^2x+1=(5^3)^x =2x+1+5x x=1/7

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 5^2x+1=125^x My answer 5^2x+1=(5^3)^x =2x+1+5x x=1/7      Log On


   

Question 324555: 5^2x+1=125^x
My answer
5^2x+1=(5^3)^x
=2x+1+5x
x=1/7
Answer by Alan3354(69443) About Me  (Show Source):
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5^2x+1=125^x
My answer
5^2x+1=(5^3)^x
=2x+1+5x
x=1/7
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Sub 1/7 for x and check:
5^(2/7 + 1) =? 125^(1/7)
5^(9/7) =? 5^(3/7)
Not equal.
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5^2x+1=125^x
My answer
5^2x+1=(5^3)^x
=2x+1+5x There's nothing on the left of the equal sign???
x=1/7
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5^2x+1=125^x
My answer
5^(2x+1)=(5^3)^x
5^(2x+1)=5^3x
2x+1 = 3x
x = 1