SOLUTION: Write the slope-intercept and point slope forms of the equation for the given situation of the line that goes through the point (-4, 5) and is perpendicular to the line 8x-6y=-13.

Algebra ->  Linear-equations -> SOLUTION: Write the slope-intercept and point slope forms of the equation for the given situation of the line that goes through the point (-4, 5) and is perpendicular to the line 8x-6y=-13.      Log On


   

Question 324287: Write the slope-intercept and point slope forms of the equation for the given situation of the line that goes through the point (-4, 5) and is perpendicular to the line 8x-6y=-13.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First find the slope.
8x-6y=-13
6y=8x%2B13
y=%284%2F3%29x%2B13%2F6
The slope of this line is m1=4%2F3
Perpendicular lines have slopes that are negative reciprocals,
m1%2Am2=-1
%284%2F3%29%2Am2=-1
m2=-3%2F4
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y=-%283%2F4%29x%2Bb
Use the point, (-4,5), to solve for b.
5=-%283%2F4%29%28-4%29%2Bb
b%2B3=5
b=2
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highlight%28y=-%283%2F4%29x%2B2%29
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Point slope form would be,
y-yp=m%28x-xp%29
y-5=-%283%2F4%29%28x-%28-4%29%29
highlight%28y-5=-%283%2F4%29%28x%2B4%29%29
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