SOLUTION: I have been struggling with this problem: x(x+6)=0 I just don't understand the steps to get the answer. Can you show me step by step to solve this? This problem was in a chapte

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I have been struggling with this problem: x(x+6)=0 I just don't understand the steps to get the answer. Can you show me step by step to solve this? This problem was in a chapte      Log On


   

Question 324208: I have been struggling with this problem:
x(x+6)=0
I just don't understand the steps to get the answer. Can you show me step by step to solve this? This problem was in a chapter for factoring. The only directions for this problem was to solve.
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If A%2AB=0 (A times B equals zero), then either A=0 or B=0 (or possibly both are zero)


So if x%28x%2B6%29=0, then x=0 or x%2B6=0. Solve the second equation for 'x' (by subtracting 6 from both sides) to get x=-6


So the solutions are x=0 or x=-6


Notice how if you plug in either x=0 or x=-6, at least one factor will go to zero and if you multiply everything out, everything goes to zero.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x(x+6)=0
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If the product is zero, either x or x+6 has to be zero.
--> x = 0
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x+6 = 0
x = -6
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Quadratic (2nd order) equations have 2 solutions.
Cubic (3rd order) have 3, etc.