SOLUTION: A vendor sells hot dogs and bags of potato chips. The first customer buys 3 hot dogs and 5 bags of chips and pays $14.74. The second customer buys 2 hot dogs and 2 bags of chips an
Algebra ->
Human-and-algebraic-language
-> SOLUTION: A vendor sells hot dogs and bags of potato chips. The first customer buys 3 hot dogs and 5 bags of chips and pays $14.74. The second customer buys 2 hot dogs and 2 bags of chips an
Log On
Question 324049: A vendor sells hot dogs and bags of potato chips. The first customer buys 3 hot dogs and 5 bags of chips and pays $14.74. The second customer buys 2 hot dogs and 2 bags of chips and pays $7.50. What is the price for each hot and each bag of chips? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A vendor sells hot dogs and bags of potato chips. The first customer buys 3 hot dogs and 5 bags of chips and pays $14.74. The second customer buys 2 hot dogs and 2 bags of chips and pays $7.50. What is the price for each hot and each bag of chips?
------------------
Equations:
3h + 5c = 14.74
2h + 2c = 7.50
--------------------------
Multiply 1st Eq. by 2
Multiply 2nd Eq. by 3
--------------------------
6h + 10c = 29.48
6h + 6c = 22.50
-----------------------
Subtract 2nd from 1st.
4c = 6.98
c = $1.75 (cost of an order of chips)
--
Since 2h+2c = 7.50
2h + 2(1.75) = 7.50
2h = 4
h = $2.00 (cost of a hot dog)
===================================
Cheers,
Stan H.
(