SOLUTION: What is the equation of the line perpendicular to the line joining (4, 2) and (3, -5) and passing through (4, 2)?
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Question 323902: What is the equation of the line perpendicular to the line joining (4, 2) and (3, -5) and passing through (4, 2)? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! (4,2 ) (3, -5)
slope of the line joining them is
m= y2-y1/x2-x1
m=-5-2 / 3-4
=-7/-1
m=7
so the general equation is y=7x+b
plug the value of any one poin to get the value of b
2=28+b
b=-26
The line perpendicular to it will have slope o -1/7
The equation for that lineis y= -1/7 x -26
