SOLUTION: This is one of my daughters homework problems. I can not find an example in the text that she can apply to the problem, Can someone please explain the necessary steps.
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-> SOLUTION: This is one of my daughters homework problems. I can not find an example in the text that she can apply to the problem, Can someone please explain the necessary steps.
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Question 32385This question is from textbook
: This is one of my daughters homework problems. I can not find an example in the text that she can apply to the problem, Can someone please explain the necessary steps.
Northern maywood voted 60% to 40% in favor of a water project. Southern maywood voted 90% to 10% against the project. The project passed 55% to 45%. If 5900 people voted how many were from southern maywood. This question is from textbook
You can put this solution on YOUR website! Northern maywood voted 60% to 40% in favor of a water project. Southern maywood voted 90% to 10% against the project. The project passed 55% to 45%. If 5900 people voted how many were from southern maywood.
Northern maywood voted 60% to 40% in favor of a water project. Southern maywood voted 90% to 10% against the project. The project passed 55% to 45%. If 5900
let people who voted from southern maywood be S
SO people who voted from NORthern maywood = 5900 - S
VOTES FOR PROJECT FROM SOUTHERN MAYWOOD = S*10/100=S/10
VOTES FOR PROJECT FROM NORTHERN MAYWOOD = (5900 - S)*60/100= 6(5900-S)/10
TOTAL VOTES FOR PROJECT =S/10 + 6(5900-S)/10=(S+35400-6S)/10=(35400-5S)/10
PERCENT VOTES FOR THE PROJECT = (35400-5S)*100/(10*5900)=55
35400-5S=55*590
5S = 35400-55*590=2950
S=2950/5=590
